Turnering #12

Butler over 3 gange, A-rækken

Par-turnering

Led
Modstandere
Kontrakt
Udspil
Stik
Score
NS
ØV
Score
Point
NS
ØV
Point
Runde
  • 26
    ØV
    Sidse Lønborg - Maja Palmø
    V 3UT 
    Q
    7
    200
    200
    7,0
      -7,0
      -7,0
    -14,0
  • 27
    V 3UT 
    ♠T
    4
    250
    250
    4,0
      -4,0
      -4,0
  • 28
    N 3UT 
    ♣Q
    11
    660
    660
    -1,0
        1,0
        1,0
  • 29
    Ø 3 
    ♣2
    10
    -130
    -130
    3,0
      -3,0
      -3,0
  • 30
    S 3♠ 
    J
    7
    -100
    -100
    1,0
      -1,0
      -1,0
  • 6
    ØV
    Berit Eickhardt - Kurt Boysen
    Ø 4♠ 
    2
    11
    -650
    -650
    0,0
        0,0
        0,0
    23,0
  • 7
    Ø 3 
    ♠Q
    10
    -130
    -130
    -4,0
        4,0
        4,0
  • 8
    S 4♠ 
    4
    12
    480
    480
    1,0
      -1,0
      -1,0
  • 9
    Ø 4♠ 
    ♣2
    10
    -620
    -620
    -8,0
        8,0
        8,0
  • 10
    N 3UT 
    4
    8
    -100
    -100
    -12,0
      12,0
      12,0
  • 11
    ØV
    Else Andersen - Erling Andersen
    V 5♠ 
    A
    11
    -450
    -450
    -5,0
        5,0
        5,0
    11,0
  • 12
    N 3UT 
    ♣3
    8
    -100
    -100
    0,0
        0,0
        0,0
  • 13
    Ø 1UT 
    ♣8
    7
    -90
    -90
    -5,0
        5,0
        5,0
  • 14
    S 2♠ 
    ♣9
    10
    170
    170
    3,0
      -3,0
      -3,0
  • 15
    Ø 3UT 
    ♣5
    10
    -430
    -430
    -4,0
        4,0
        4,0
  • 21
    ØV
    Lone Seidelin - Anne Hansen
    V 3 
    ♣T
    9
    -110
    -110
    -2,0
        2,0
        2,0
    15,0
  • 22
    S 3UT 
    ♠9
    7
    -100
    -100
    -10,0
      10,0
      10,0
  • 23
    S 2♠ 
    A
    11
    200
    200
    -6,0
        6,0
        6,0
  • 24
    Ø 4 
    ♠2
    9
    50
    50
    2,0
      -2,0
      -2,0
  • 25
    P  
    0
    0
    1,0
      -1,0
      -1,0
  • 1
    NS
    Jytte Møller Jensen - Knud Jensen
    V 2 
    7
    7
    50
    50
        0,0
        0,0
    0,0
    -7,0
  • 2
    Ø 4♣ 
    A
    11
    -150
    -150
      -2,0
      -2,0
    2,0
  • 3
    V 2 
    ♣K
    8
    -90
    -90
      -2,0
      -2,0
    2,0
  • 4
    N 1 
    ♠8
    9
    140
    140
      -1,0
      -1,0
    1,0
  • 5
    Ø 3 
    7
    9
    -110
    -110
      -2,0
      -2,0
    2,0
  • 16
    NS
    Inge Dahm - Inger Just (S)
    Ø 3 
    A
    9
    -140
    -140
      -1,0
      -1,0
    1,0
    14,0
  • 17
    Ø 2 
    ♠A
    10
    -130
    -130
        3,0
        3,0
    -3,0
  • 18
    S 2 
    ♠9
    8
    110
    110
        1,0
        1,0
    -1,0
  • 19
    V 3UT 
    7
    7
    200
    200
        7,0
        7,0
    -7,0
  • 20
    Ø 2♠ 
    9
    7
    100
    100
        4,0
        4,0
    -4,0