Turnering #122

Finale par 2023-24, A-rækken

Parturnering

Led
Modstandere
Kontrakt
Udspil
Stik
Score
NS
ØV
Score
Point
NS
ØV
Point
Runde
  • 1
    NS
    Christian V. M. Herold - Mette Herold
    S 1UT 
    7
    5
    -100
    -100
        3,0
        3,0
    -3,0
    -81,0
  • 2
    N 2♠ 
    2
    7
    -100
    -100
        2,0
        2,0
    -2,0
  • 3
    V 3UT D
    ♣Q
    9
    -750
    -750
    -85,0
    -85,0
    85,0
  • 4
    N 4 
    ♠2
    11
    650
    650
        2,0
        2,0
    -2,0
  • 5
    S 1UT 
    J
    6
    -100
    -100
    -11,0
    -11,0
    11,0
  • 6
    N 1 
    A
    6
    -50
    -50
        8,0
        8,0
    -8,0
  • 7
    ØV
    Ivan Abel - Marit Abel
    S 6♠ 
    3
    12
    1430
    1430
    64,0
    -64,0
    -64,0
    -120,0
  • 8
    Ø 2♠ 
    A
    9
    -140
    -140
    -14,0
      14,0
      14,0
  • 9
    Ø 5 D
    ♠Q
    9
    500
    500
    59,0
    -59,0
    -59,0
  • 10
    V 3♠ 
    A
    6
    300
    300
    -10,0
      10,0
      10,0
  • 11
    Ø 4 
    K
    10
    -420
    -420
    -11,0
      11,0
      11,0
  • 12
    N 2 
    ♣6
    8
    110
    110
    32,0
    -32,0
    -32,0
  • 19
    ØV
    Per Marquardsen - Jørn Lorentzen
    S 4♠ 
    8
    10
    420
    420
    50,0
    -50,0
    -50,0
    -24,0
  • 20
    Ø 3UT 
    7
    8
    100
    100
    15,0
    -15,0
    -15,0
  • 21
    N 3UT 
    ♣2
    8
    -100
    -100
    -38,0
      38,0
      38,0
  • 22
    N 4♠ 
    ♣Q
    10
    420
    420
    19,0
    -19,0
    -19,0
  • 23
    S 2♣ 
    3
    10
    130
    130
    -19,0
      19,0
      19,0
  • 24
    N 2♣ 
    A
    7
    -50
    -50
    -3,0
        3,0
        3,0
  • 25
    ØV
    Per Slouborg - Dimitris Trifonopoulos
    Ø 5 
    ♣5
    10
    100
    100
    39,0
    -39,0
    -39,0
    68,0
  • 26
    Ø 3UT 
    ♣T
    9
    -600
    -600
    -64,0
      64,0
      64,0
  • 27
    N 2 
    A
    8
    110
    110
    27,0
    -27,0
    -27,0
  • 28
    Ø 2 
    ♣8
    9
    -110
    -110
    -4,0
        4,0
        4,0
  • 29
    Ø 3UT 
    A
    10
    -630
    -630
    -75,0
      75,0
      75,0
  • 30
    S 4♠ 
    4
    12
    480
    480
    9,0
      -9,0
      -9,0
  • 13
    ØV
    Anders Hagemann - Thomas Binder
    N 6 
    ♠8
    11
    -100
    -100
    -75,0
      75,0
      75,0
    115,0
  • 14
    V 3UT 
    J
    10
    -430
    -430
    -20,0
      20,0
      20,0
  • 15
    V 3♠ D
    Q
    8
    100
    100
    38,0
    -38,0
    -38,0
  • 16
    N 4♠ 
    2
    8
    -100
    -100
    -32,0
      32,0
      32,0
  • 17
    N 5♠ 
    ♣A
    12
    480
    480
    -11,0
      11,0
      11,0
  • 18
    V 2 
    ♣K
    8
    -110
    -110
    -15,0
      15,0
      15,0