Turnering #115

Indledende par 2023, B-rækken

Parturnering

Led
Modstandere
Kontrakt
Udspil
Stik
Score
NS
ØV
Score
Point
NS
ØV
Point
Runde
  • 1
    ØV
    Lisbeth Brink - Lisbeth Truelsen
    V 1 
    J
    6
    50
    50
    47,0
    -47,0
    -47,0
    -170,0
  • 2
    Ø 4♠ 
    ♠4
    10
    -420
    -420
    2,0
      -2,0
      -2,0
  • 3
    Ø 2 
    ♠A
    9
    -140
    -140
    2,0
      -2,0
      -2,0
  • 4
    Ø 1UT 
    2
    7
    -90
    -90
    3,0
      -3,0
      -3,0
  • 5
    Ø 4 D
    ♠9
    7
    500
    500
    80,0
    -80,0
    -80,0
  • 6
    N 4 
    ♠T
    10
    420
    420
    36,0
    -36,0
    -36,0
  • 25
    NS
    Jon Norup - Otto Poulsen
    N 3UT 
    6
    8
    -50
    -50
    -26,0
    -26,0
    26,0
    -33,0
  • 26
    S 4 
    ♠A
    9
    -100
    -100
      27,0
      27,0
    -27,0
  • 27
    S 3 
    ♠A
    11
    200
    200
    -17,0
    -17,0
    17,0
  • 28
    V 2♠ 
    ♣A
    8
    -110
    -110
    -15,0
    -15,0
    15,0
  • 29
    N 3♠ 
    J
    10
    170
    170
      -3,0
      -3,0
    3,0
  • 30
    S 3UT 
    K
    8
    -50
    -50
        1,0
        1,0
    -1,0
  • 19
    NS
    Lisbeth Christensen - Jutta Madsen
    N 4 
    ♠3
    10
    420
    420
      89,0
      89,0
    -89,0
    104,0
  • 20
    N 4♠ 
    4
    11
    650
    650
      30,0
      30,0
    -30,0
  • 21
    Ø 2UT D
    7
    12
    -890
    -890
    -64,0
    -64,0
    64,0
  • 22
    V 2UT 
    ♠5
    9
    -150
    -150
        8,0
        8,0
    -8,0
  • 23
    Ø 2UT 
    ♠7
    9
    -150
    -150
      24,0
      24,0
    -24,0
  • 24
    V 4 
    ♠6
    9
    50
    50
      17,0
      17,0
    -17,0
  • 13
    ØV
    Anita Vind Petersen (S) - Lasse Petersen (S)
    N 4 
    ♠5
    13
    710
    710
    6,0
      -6,0
      -6,0
    -17,0
  • 14
    Ø 1UT 
    ♣3
    7
    -90
    -90
    1,0
      -1,0
      -1,0
  • 15
    S 3UT 
    ♠7
    8
    -100
    -100
    -13,0
      13,0
      13,0
  • 16
    Ø 2♣ 
    A
    8
    -90
    -90
    -6,0
        6,0
        6,0
  • 17
    N 4♠ 
    ♣2
    12
    480
    480
    13,0
    -13,0
    -13,0
  • 18
    Ø 3UT 
    Q
    6
    150
    150
    16,0
    -16,0
    -16,0
  • 7
    NS
    Anette Holler - Kirsten Frydensbjerg (S)
    S 4♠ 
    3
    10
    620
    620
      -7,0
      -7,0
    7,0
    -140,0
  • 8
    S 2 
    2
    6
    -100
    -100
    -11,0
    -11,0
    11,0
  • 9
    N 3♠ 
    K
    6
    -150
    -150
    -14,0
    -14,0
    14,0
  • 10
    N 2 
    3
    11
    150
    150
    -92,0
    -92,0
    92,0
  • 11
    Ø 2 
    3
    7
    50
    50
      14,0
      14,0
    -14,0
  • 12
    N 4 
    5
    9
    -100
    -100
    -30,0
    -30,0
    30,0