Turnering #383

Monrad butler - 2 i 1, A-rækken

Parturnering

Led
Modstandere
Kontrakt
Udspil
Stik
Score
NS
ØV
Score
Point
NS
ØV
Point
Runde
  • 1
    ØV
    Peter Schmidt - Claus Tegtmeier
    S 2♠ D
    A
    5
    -500
    -500
    -7,0
        7,0
        7,0
    11,0
  • 2
    V 3♣ 
    Q
    8
    50
    50
    2,0
      -2,0
      -2,0
  • 3
    N 4 
    ♣6
    11
    450
    450
    0,0
        0,0
        0,0
  • 4
    S 3UT 
    8
    12
    690
    690
    -4,0
        4,0
        4,0
  • 5
    Ø 2♠ 
    7
    7
    50
    50
    3,0
      -3,0
      -3,0
  • 6
    S 5♠ 
    A
    12
    480
    480
    -2,0
        2,0
        2,0
  • 7
    Ø 4♠ 
    ♣K
    11
    -650
    -650
    0,0
        0,0
        0,0
  • 8
    S 4♠ 
    ♣A
    9
    -50
    -50
    -3,0
        3,0
        3,0
  • 9
    S 2♠ 
    K
    8
    110
    110
    0,0
        0,0
        0,0
  • 10
    Ø 1UT 
    5
    7
    -90
    -90
    0,0
        0,0
        0,0
  • 11
    ØV
    Ejgild Johansen - Torben Ebbesen
    N 4 
    ♠J
    11
    450
    450
    6,0
      -6,0
      -6,0
    -11,0
  • 12
    Ø 3UT 
    6
    9
    -400
    -400
    -1,0
        1,0
        1,0
  • 13
    V 4 
    ♠J
    9
    100
    100
    6,0
      -6,0
      -6,0
  • 14
    N 2♠ 
    ♠K
    8
    110
    110
    2,0
      -2,0
      -2,0
  • 15
    Ø 6 
    J
    13
    -940
    -940
    -3,0
        3,0
        3,0
  • 16
    N 4♠ 
    A
    10
    420
    420
    7,0
      -7,0
      -7,0
  • 17
    N 3 
    T
    9
    140
    140
    2,0
      -2,0
      -2,0
  • 18
    Ø 3 
    A
    9
    -140
    -140
    -2,0
        2,0
        2,0
  • 19
    N 2♠ 
    ♠8
    8
    110
    110
    2,0
      -2,0
      -2,0
  • 20
    V 3♣ 
    A
    8
    100
    100
    -8,0
        8,0
        8,0
  • 21
    ØV
    Anders Nordstrøm - Brian Johansen
    V 6♣ 
    T
    13
    -940
    -940
    7,0
      -7,0
      -7,0
    1,0
  • 22
    N 4♠ 
    6
    10
    420
    420
    7,0
      -7,0
      -7,0
  • 23
    V 2 
    4
    8
    -110
    -110
    -4,0
        4,0
        4,0
  • 24
    Ø 2♠ 
    K
    7
    50
    50
    -3,0
        3,0
        3,0
  • 25
    V 2♠ 
    ♣A
    8
    -110
    -110
    -4,0
        4,0
        4,0
  • 26
    S 4♠ 
    ♣T
    11
    650
    650
    5,0
      -5,0
      -5,0
  • 27
    S 2 
    J
    7
    -50
    -50
    -4,0
        4,0
        4,0
  • 28
    V 3UT 
    ♠7
    12
    -490
    -490
    2,0
      -2,0
      -2,0
  • 29
    Ø 2 
    A
    10
    -130
    -130
    2,0
      -2,0
      -2,0
  • 30
    Ø 4 
    ♠8
    10
    -420
    -420
    -9,0
        9,0
        9,0