Turnering #115

Indledende par 2023, B-rækken

Parturnering

Led
Modstandere
Kontrakt
Udspil
Stik
Score
NS
ØV
Score
Point
NS
ØV
Point
Runde
  • 19
    ØV
    (Oversidder)
      
    M
    M*
    0,0
    -13,0
    -13,0
    -77,8
  • 20
      
    M
    M*
    0,0
    -13,0
    -13,0
  • 21
      
    M
    M*
    0,0
    -13,0
    -13,0
  • 22
      
    M
    M*
    0,0
    -13,0
    -13,0
  • 23
      
    M
    M*
    0,0
    -13,0
    -13,0
  • 24
      
    M
    M*
    0,0
    -13,0
    -13,0
  • 7
    NS
    Anders Hagemann - Thomas Binder
    V 4♠ 
    ♣7
    10
    -620
    -620
    -16,0
    -16,0
    16,0
    -66,0
  • 8
    S 3 
    Q
    8
    -50
    -50
    -13,0
    -13,0
    13,0
  • 9
    Ø 2 
    ♠A
    8
    -110
    -110
    -42,0
    -42,0
    42,0
  • 10
    Ø 2♠ 
    5
    9
    -140
    -140
      -6,0
      -6,0
    6,0
  • 11
    V 4 
    ♠J
    11
    -450
    -450
    -15,0
    -15,0
    15,0
  • 12
    N 6 
    3
    13
    1460
    1460
      26,0
      26,0
    -26,0
  • 13
    ØV
    Abelone Dyrup - Peter J. Lauritzen
    Ø 5♣ 
    8
    10
    100
    100
    62,0
    -62,0
    -62,0
    -163,0
  • 14
    S 5 
    ♠K
    11
    400
    400
    44,0
    -44,0
    -44,0
  • 15
    N 2 
    ♠K
    7
    -100
    -100
    -3,0
        3,0
        3,0
  • 16
    V 3UT 
    ♣T
    10
    -630
    -630
    -20,0
      20,0
      20,0
  • 17
    N 3UT 
    A
    9
    400
    400
    46,0
    -46,0
    -46,0
  • 18
    Ø 3 
    7
    8
    50
    50
    34,0
    -34,0
    -34,0
  • 25
    ØV
    Flemming Bak Jensen - Svend Vinther-Knudsen
    Ø 2 
    ♣9
    5
    300
    300
    14,0
    -14,0
    -14,0
    -9,0
  • 26
    Ø 2 
    4
    8
    -110
    -110
    -16,0
      16,0
      16,0
  • 27
    S 3UT 
    3
    10
    430
    430
    32,0
    -32,0
    -32,0
  • 28
    S 3UT 
    5
    10
    630
    630
    35,0
    -35,0
    -35,0
  • 29
    V 2 
    ♠A
    9
    -140
    -140
    -12,0
      12,0
      12,0
  • 30
    V 4 
    ♣T
    10
    -420
    -420
    -44,0
      44,0
      44,0
  • 1
    ØV
    Holger Larsen (S) - Jette Marie Steffensen
    V 2 
    ♠K
    9
    -140
    -140
    -13,0
      13,0
      13,0
    -73,0
  • 2
    Ø 3UT 
    ♣8
    11
    -460
    -460
    14,0
    -14,0
    -14,0
  • 3
    N 5♣ 
    ♠7
    10
    -50
    -50
    -1,0
        1,0
        1,0
  • 4
    V 3 
    A
    8
    100
    100
    43,0
    -43,0
    -43,0
  • 5
    Ø 3UT 
    ♣Q
    8
    50
    50
    50,0
    -50,0
    -50,0
  • 6
    V 1UT 
    ♣3
    7
    -90
    -90
    -20,0
      20,0
      20,0